College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 59


$\left\{-2\sqrt{2}, 2\sqrt{2}\right\}$

Work Step by Step

Add $64$ to both sides: $8x^2=64$ Divide $8$ on both sides to obtain: $x^2=8$ Factor $8$ so that one factor is a perfect square: $x=\pm \sqrt{4(2)} \\x=\pm \sqrt{2^2(2)} \\x=\pm 2\sqrt{2}$ Thus, the solution set of the given equation is $\left\{-2\sqrt{2}, 2\sqrt{2}\right\}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.