## College Algebra 7th Edition

$\left\{\dfrac{4-\sqrt{7}}{3}, \dfrac{4+\sqrt{7}}{3}\right\}$
Take the square root of both sides to obtain: $3x-4 = \pm \sqrt{7}$ Add 4 on both sides of the equation to obtain: $3x=4 \pm \sqrt{7}$ Divide 3 on both sides of the equation to obtain: $x =\dfrac{4\pm \sqrt{7}}{3}$ Thus, the solution set of the given equation is $\left\{\dfrac{4-\sqrt{7}}{3}, \dfrac{4+\sqrt{7}}{3}\right\}$.