Answer
NO SOLUTION as $x \ne - 10$
Work Step by Step
$\log(2x-1) = \log(x+3) + \log 3$
$\log (2x-1) = \log [3(x+3)]$
$\log (2x-1) = \log (3x + 9)$
$\log(2x-1)-\log(3x+9) = 0$
$\log \frac{2x-1}{3x+9} = 0$
$1 = \frac{2x-1}{3x+9} $
$\frac{2x-1}{3x+9} = 1$
$2x - 1 = 1(3x+9)$
$2x - 1 = 3x + 9$
$2x - 3x - 1 - 9 = 0$
$-x - 10 = 0$
$-x = 10$
$x = -10$
NO SOLUTION as $x \ne - 10$
