College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 63

Answer

$x\approx0.61$

Work Step by Step

Use the definition of the natural log function to solve for $x$. Rewrite the problem so that the base has the exponent of the opposite side and is equal to the log's number and/or variable. $6+2\ln x=5$ $2\ln x=-1$ $\ln x=-\frac{1}{2}$ $e^{-\frac{1}{2}}=x$ $x\approx0.61$
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