College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 39



Work Step by Step

Find the natural log of both sides and then pull out the exponent to the left side. Then solve for $x$. $7^{0.3x}=813$ $\ln(7^{0.3x})=\ln(813)$ $0.3x\ln(7)=\ln(813)$ $0.3x=\frac{\ln(813)}{\ln(7)}$ $x=\frac{\ln(813)}{\ln(7)}\times\frac{1}{0.3}$ $x\approx11.48$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.