Answer
Since $x \ne \frac{-5-\sqrt {37}}{2}$, then $x = \frac{-5+\sqrt {37}}{2}$
Work Step by Step
$\ln 3 - \ln(x+5) - \ln x = 0$
$\ln \frac{3}{x+5} = \ln x$
$\frac{3}{x+5} = x$
$3 = x(x+5)$
$3 = x^{2} + 5x$
$x^{2} + 5x - 3 = 0$
$x = \frac{-b±\sqrt {b^{2}-4ac}}{2a}$
$x = \frac{-(5)±\sqrt {5^{2}-4(1)(-3)}}{2(1)}$
$x = \frac{-5±\sqrt {25+12}}{2}$
$x = \frac{-5±\sqrt {37}}{2}$
Since $x \ne \frac{-5-\sqrt {37}}{2}$, then $x = \frac{-5+\sqrt {37}}{2}$
