College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 58

Answer

$x\approx-1.98$

Work Step by Step

Use the definition of the log function to solve for $x$. Rewrite the problem so that the base has the exponent of the opposite side and is equal to the log's number and/or variable. $\log_7(x+2)=-2$ $7^{-2}=x+2$ $7^{-2}-2=x$ $\frac{1}{49}-\frac{98}{49}=x$ $x\approx-1.98$
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