College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 28

Answer

$x=1.69$

Work Step by Step

Make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $19^x=143$ $x\ln(19)=\ln(143)$ $x=\frac{\ln(143)}{\ln(19)}$ $x=1.69$
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