College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 36



Work Step by Step

Find the natural log of both sides and then pull out the exponent to the left side ($\ln$ and $e$ cancel each other out). Then solve for $x$. $e^{4x-5}-7=11243$ $e^{4x-5}=11250$ $4x-5=\ln(11250)$ $4x=\ln(11250)+5$ $x=\frac{\ln(11250)+5}{4}$ $x\approx3.58$
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