## College Algebra (6th Edition)

$x\approx3.58$
Find the natural log of both sides and then pull out the exponent to the left side ($\ln$ and $e$ cancel each other out). Then solve for $x$. $e^{4x-5}-7=11243$ $e^{4x-5}=11250$ $4x-5=\ln(11250)$ $4x=\ln(11250)+5$ $x=\frac{\ln(11250)+5}{4}$ $x\approx3.58$