Answer
$x=0$
Work Step by Step
Begin by factoring the terms using trial and error. Then set the terms in each set of parentheses equal to $0$ and solve for $x$ by using the natural log on both sides of each equation.
$3^{2x}+3{x}-2=0$
$(3^x-1)(3^x+2)=0$
$3^x=1, 3^x=-2$
$x=0$, not possible
