College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 34



Work Step by Step

Find the natural log of both sides and then pull out the exponent to the left side ($\ln$ and $e$ cancel each other out). Then solve for $x$. $e^{1-8x}=7957$ $1-8x=\ln(7957)$ $8x=1-\ln(7957)$ $x=\frac{1-\ln(7957)}{8}$ $x\approx-1.00$
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