College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 29



Work Step by Step

Divide both sides by $5$. Then make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $5e^x=23$ $e^x=\frac{23}{5}$ $x\ln(e)=\ln(\frac{23}{5})$ $x=\frac{\ln(\frac{23}{5})}{\ln(e)}$ $x=1.53$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.