College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 74

Answer

$x = 3$

Work Step by Step

$3\log_2 (x-1) = 5 - \log_2 4$ $\log_2 (x-1)^{3} = 5 - \log_2 2^{2}$ $\log_2 (x-1)^{3} = 5 - 2$ $\log_2 (x-1)^{3} = 3$ $(2)^{3} = (x-1)^{3}$ $(2) = (x -1)$ $2 + 1 = x$ $x = 3$
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