College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 44



Work Step by Step

Begin by factoring the terms using trial and error. Then set the terms in each set of parentheses equal to $0$ and solve for $x$ by using the natural log on both sides of each equation. $e^{2x}-2e^x-3=0$ $(e^x-3)(e^x+1)=0$ $e^x-3=0, e^x+1=0$ $e^x=3, e^x=-1$ $x\approx1.10$, not possible $x\approx1.10$
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