## College Algebra (6th Edition)

$x\approx3.39$
Use the definition of the natural log function to solve for $x$. Rewrite the problem so that the base has the exponent of the opposite side and is equal to the log's number and/or variable. $\ln\sqrt {x+4}=1$ $e^1=\sqrt {x+4}$ $x+4=e^2$ $x=e^2-4$ $x\approx3.39$