Answer
$x = 2$
Work Step by Step
$\log_4(x+2) - \log_4(x-1) = 1$
$\log_4 \frac{(x+2)}{(x-1)} = 1$
$4 = \frac{(x+2)}{(x-1)}$
$4(x-1) = x + 2$
$4x - 4 = x + 2$
$4x - x -2 -4 = 0$
$3x - 6 = 0$
$3x = 6$
$x = 2$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 72
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
