College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 72

Answer

$x = 2$

Work Step by Step

$\log_4(x+2) - \log_4(x-1) = 1$ $\log_4 \frac{(x+2)}{(x-1)} = 1$ $4 = \frac{(x+2)}{(x-1)}$ $4(x-1) = x + 2$ $4x - 4 = x + 2$ $4x - x -2 -4 = 0$ $3x - 6 = 0$ $3x = 6$ $x = 2$
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