College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 102

Answer

Since $x \ne -2$, then $x = 6$

Work Step by Step

$3^{x^{2}-12} = 9^{2x}$ $3^{x^{2}-12} = (3^{2})^{2x}$ $3^{x^{2}-12} = 3^{4x}$ $x^{2} - 12 = 4x$ $x^{2} - 4x - 12 = 0$ $(x-6)(x+2) = 0$ $x = 6, -2$ Since $x \ne -2$, then $x = 6$
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