College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 26

Answer

$x=-0.19$

Work Step by Step

Make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $e^x=0.83$ $x\ln(e)=\ln(0.83)$ $x=\frac{\ln(0.83)}{\ln(e)}$ $x=-0.19$
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