## College Algebra (6th Edition)

$x\approx6.06$
Find the natural log of both sides and then pull out the exponent to the left side. Then solve for $x$. $5^{x-3}=137$ $\ln(5^{x-3})=\ln(137)$ $(x-3)\ln(5)=\ln(137)$ $(x-3)=\frac{\ln(137)}{\ln(5)}$ $x=3+\frac{\ln(137)}{\ln(5)}$ $x\approx6.06$