Answer
$K.E=7.72\times10^{-21}J$
Work Step by Step
The average Kinetic energy for molecules of an ideal gas can be found from the formula:
$K.E=(\frac{3}{2})(\frac{R}{N_{A}})T$................eq(1)
We first need to convert the temperature to Kelvin:
$T=C^{\circ}+273=100+273=373K$
Now, we substitute the values of $R,T$ and $N_A$ in eq(1) and solve:
$K.E=(\frac{3}{2})(\frac{8.314}{6.023\times10^{23}})(373)$
$K.E=7.72\times10^{-21}J$
