Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 43a

Answer

$Q=3.49KJ$

Work Step by Step

The energy transferred to gas as heat can be calculated from the formula: $Q=nC_P\Delta T$ Since we know that $C_P=\frac{7}{2}R$, the above formula can be written as: so $Q=n\frac{7}{2}R\Delta T$ Putting the values of $n,R$ and $\DeltaT$ in the formula and solving, we get: $Q=3\times\frac{7}{2}(8.314)(40)$ $Q=3.49\times10^3J$ $Q=3.49KJ$
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