Answer
$Yes$
Work Step by Step
From 35(a) and 35(b), we know that $v_{avg}=420\frac{m}{s}$ and $v_{rms}=458\frac{m}{s}$ respectively.
Therefore, it is clear that $v_{rms}>v_{avg}$.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 35c
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