Answer
$$10.7$$
Work Step by Step
The average translational kinetic energy is
$$
K_{\mathrm{avg}}=\frac{3}{2} k T=\frac{3}{2}\left(1.38 \times 10^{-23} \mathrm{J} / \mathrm{K}\right)[(32.0+273.15) \mathrm{K}]=6.32 \times 10^{-21} \mathrm{J}
$$
The ratio
$\varepsilon / K_{\mathrm{avg}}$ is $$\left(6.76 \times 10^{-20} \mathrm{J}\right) /\left(6.32 \times 10^{-21} \mathrm{J}\right)=10.7$$
