Answer
$T=7\times 10^3K$
Work Step by Step
We know that;
$T=\frac{2g_mR_mM}{3R}$.......eq(1)
Radius of moon, $R_m=1.74\times 10^6m$
$g_m=0.16g=0.16\times 9.8\frac{m}{s^2}$
For Oxygen$ (O_2)$, $M=32\times 10^{-3}\frac{kg}{mol}$
We plug in the known values in eq(1) to obtain:
$T=\frac{2(0.16\times 9.8)\times 1.74\times 10^6\times 32\times 10^{-3}}{3(8.31)}=7\times 10^3K$
