Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 28

Answer

3.68$\times$$10^{9}$ Hz

Work Step by Step

p = 1 atm = 101325 Pa T = 0.00$^{\circ}$C = 273.15 K d = 3.0$\times$$10^{-8}$cm = 3.0$\times$$10^{-10}$m Speed of sound in the air $v_{sound}$ = 343 m/s Boltzman constant k = 1.38 $\times 10^{-23}$ Using mean free path equation λ = $\frac{kT}{\sqrt 2 \times π \times d^{2}\times p}$ We calculated wavelenght of sound in air: $λ_{sound}$ = 1.38$\times 10^{-23}$ $\times$ $\frac{273.15}{\sqrt 2\timesπ\times (3.0\times10^{-10})^{2}\times101325}$ = 9.3$\times10^{-8}$ Frequency of a wavelenght can be calculated by $f = \frac{v}{λ}$ $f_{sound}$ = $\frac{343}{9.3 \times 10^{-8}}$ $f_{sound}$ = 3.68$\times$$10^{9}$ Hz
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