Answer
$v_{rms}=490m/s$
Work Step by Step
From the given graph, $v_{p}=400m/s$
We have a relation, $v_{rms}=\sqrt \frac{3}{2}*v_{p}$
or, $v_{rms}=\sqrt \frac{3}{2}\times400= 490m/s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 38b
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