Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 42

Answer

$E_{internal}=3.4KJ$

Work Step by Step

The internal energy of gas can be calculated as $E_{interanl}=\frac{3}{2}nRT$ The data in the question stipulates that $n=1$ and $T=273$. We already know that $R=8.314$. Substituting these values in the formula: $E_{internal}=\frac{3}{2}(1)(8.314)(273)=3.4\times10^3J$ $E_{internal}=3.4KJ$
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