Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 25c

Answer

$3.40$ KJ

Work Step by Step

Average Kinetic energy per mole can be determined as: $K.E \times N_{a}=5.65\times10^{-21}\times6.023\times10^{23}$ $K.E \times N_{a}=3402$ $K.E \times N_{a}=3.4\times10^{3}$ $K.E \times N_{a}=3.4KJ$
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