Answer
$v_{avg}=420\frac{m}{s}$
Work Step by Step
The average speed of the particles can be calculated as
$v_{avg}=\frac{1}{N}\Sigma_{i=1}^Nv_i$
Substituting the values in the formula and solving, we get:
$v_{avg}=\frac{1}{10}(4(200)+2(500)+4(600))$
$v_{avg}=420\frac{m}{s}$
