Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 579: 25d

Answer

$4.65KJ$

Work Step by Step

Average Kinetic energy per mole can be determined as: $K.E\times N_a=7.72\times10^{-21}\times6.023\times10^{23}$ $K.E\times N_a=4649$ $K.E\times N_a=4.65KJ$
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