Answer
$T=4.4\times 10^2K$
Work Step by Step
We know that;
$T=\frac{2g_mR_mM}{3R}$.......eq(1)
Radius of moon; $R_m=1.74\times 10^6m$
$g_m=0.16g=0.16\times 9.8\frac{m}{s^2}$
For Hydrogen, $M=2\times 10^{-3}\frac{kg}{mol}$
We plug in the known values in eq(1) to obtain:
$T=\frac{2(0.16\times 9.8)\times 1.74\times 10^6\times 2\times 10^{-3}}{3(8.31)}=4.4\times 10^2K$
