Answer
$v_{avg}=3.2\frac{cm}{s}$
Work Step by Step
For the given scenario, $v_{avg}$ can be calculated as
$v_{avg}=\frac{\Sigma N_i v_i}{\Sigma N_i}$
Substituting the values of $N_i$ and $v_i$ into the formula, we get
$v_{avg}=\frac{2(1)+4(2)+6(3)+8(4)+2(5)\frac{cm}{s}}{(2+4+6+8+2)}$
$v_{avg}=3.2\frac{cm}{s}$
