Answer
$K.E=5.65\times10^{-21}J$
Work Step by Step
We know that the average kinetic energy for molecules of and ideal gas is found from the formula:
$K.E=(\frac{3}{2})(\frac{R}{N_{A}})T$............eq(1)
To use this formula, we first need to convert the temperature to Kelvin:
$T=C^{\circ}+273=273K$
Now substituting the values in eq(1),
$K.E=(\frac{3}{2})(\frac{8.314}{6.023\times10^{23}})(273)$
$K.E=5.65\times10^{-21}J$
