Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 578: 13a

Answer

There are $~~1.5~~$ moles of gas.

Work Step by Step

We can use the data at point $a$ to find the number of moles $n$: $PV = nRT$ $n = \frac{PV}{RT}$ $n = \frac{(2500~Pa)(1.0~m^3)}{(8.31~J/mol\cdot K)(200~K)}$ $n = 1.5~mol$ There are $~~1.5~~$ moles of gas.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.