Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 578: 13b

Answer

$T = 1800~K$

Work Step by Step

In part (a), we found that there are $1.5$ moles of gas. We can find the temperature at point $b$: $PV = nRT$ $T = \frac{PV}{nR}$ $T = \frac{(7500~Pa)(3.0~m^3)}{(1.5~mol)(8.31~J/mol\cdot K)}$ $T = 1800~K$
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