Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 578: 10

Answer

$0.2$

Work Step by Step

Given: Number of moles of first gas $n_1 = 2\ moles$ Number of moles of second gas $n_2 =0.5\ moles $ From the ideal gas equation: $PV = nRT$ We know that the formula for; pressure for first gas $P_1 =\frac{n_1RT}{V}$ Pressure for second gas $P_2 = \frac{n_2RT}{V}$ Therefore, the Total pressure is: $P= P_1+P_2$ $P= (n_1+n_2) \frac{RT}{V}$ This means that: Fraction of total pressure to the pressure on second gas is: $\frac{P_2}{P}=\frac{n_2\frac{RT}{V}}{(n_1+n_2)\frac{RT}{V}}$ $\frac{P_2}{P} = \frac{n_2}{n_1+n_2}$ $\frac{P_2}{P} = \frac{0.5}{2+0.5}$ $\frac{P_2}{P} = 0.2 $
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