Answer
$v_{rms}=442\frac{m}{s}$
Work Step by Step
$v_{rms}=\sqrt\frac{3RT}{M}$
We know from Appendix-F that, for argon, the molar mass is: $M=3.995\times10^{-2} Kgmol^{-1}$
Substituting the valuesof $R,T$ and $M$ into the formula, we get
$v_{rms}=\sqrt\frac{3(8.314)(313)}{3.995\times10^{-2}}$
$v_{rms}=442\frac{m}{s}$
