Answer
$W=207J$
Work Step by Step
Given:
$P=24.9\frac{T}{V}-0.00662\frac{T^2}{V}$
$T_o=315K$
$T=325K$
We know this is an isobaric process ($\Delta$$P=0$), so $W=P\Delta$$V$
First, bring V to one side:
$VP=24.9{T}-0.00662{T^2}$
Find $P(V-V_o)$
$W=P\Delta$$V=P(V-V_o)=24.9*{325}-0.00662*{325^2}-24.9*{315}-0.00662*{315^2}=207J$
