Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 578: 20

Answer

$v_{rms}=2496\frac{m}{s}$

Work Step by Step

The root mean square speed is given as $v_{rms}=\sqrt\frac{3RT}{M}$ The molar mass of Helium (found from Appendix F) is $M=4.003\times10^{-3} Kg mol^{-1}$ Now, we substitute the values of $R,T$ and $M$ into the equation to find $v_{rms}$: $v_{rms}=\sqrt\frac{3(8.314)(1000)}{4.003\times10^{-3}}$ $v_{rms}=2496\frac{m}{s}$
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