Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 47

Answer

$\sum ^{100}_{k=1}k\times 2^{k+2} $

Work Step by Step

$1\times 2^{3}+2\times 2^{1}+3\times 2^{5}+4\times 2^{6}+\dots +100\times 2^{102}=1\times 2^{1+2}+2\times 2^{2+2}+3\times 2^{3+2}+4\times 2^{4+2}+\dots+100\times 2^{100+2}=\sum ^{100}_{k=1}k\times 2^{k+2} $
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