Answer
$\sum ^{33}_{i=1}3i$
Work Step by Step
$3+6+9+12+\ldots +99=3\times \left( 1\right) +3\times \left( 2\right) +3\times \left( 3\right) +3\times \left( 4\right) +\ldots +3\times \left( 33\right) =\sum ^{33}_{i=1}3i$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Review - Exercises - Page 890: 45
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