Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 12

Answer

(a) $a_1=\frac{5}{2}$ $a_2=\frac{5}{4}$ $a_3=\frac{5}{8}$ $a_4=\frac{5}{16}$ $a_5=\frac{5}{32}$ (b) See the graph. (c) $S_5=\frac{155}{32}$ (d) It is a geometric sequence. Common ratio: $r=\frac{1}{2}$

Work Step by Step

$a_n=\frac{5}{2^n}$ (a) $a_1=\frac{5}{2^1}=\frac{5}{2}$ $a_2=\frac{5}{2^2}=\frac{5}{4}$ $a_3=\frac{5}{2^3}=\frac{5}{8}$ $a_4=\frac{5}{2^4}=\frac{5}{16}$ $a_5=\frac{5}{2^5}=\frac{5}{32}$ (c) $S_5=a_1+a_2+a_3+a_4+a_5=\frac{5}{2}+\frac{5}{4}+\frac{5}{8}+\frac{5}{16}+\frac{5}{32}=\frac{155}{32}$ (d) $\frac{a_2}{a_1}=\frac{1}{2}$ $\frac{a_3}{a_2}=\frac{1}{2}$ $\frac{a_4}{a_3}=\frac{1}{2}$ $\frac{a_5}{a_4}=\frac{1}{2}$ It is a geometric sequence. Common ratio: $r=\frac{1}{2}$
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