Answer
(a) $A_n=35000+1200(n-1)$
(b) $43,400$ compared to $45,027$ dollars
Work Step by Step
(a) The salaries form a arithmetic sequence with $A_n=A_1+(n-1)d$=35000+1200(n-1)
(b) With $n=8$, we have $A_8=35000+1200(8-1)=43400$ dollars.
The earlier result gives a salary of $45,027.21$ of the teacher in Exercise 29 in his eighth year.
Compare the two numbers, we find that the teacher in this exercise earns less than the teacher in Exercise 29 after eight years.
