Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 44

Answer

$2^{}+2^{2}\times 2^{2}+3^{2}\times 2^{3}+\ldots +10^{2}\times 2^{10}$

Work Step by Step

$\sum ^{10}_{n=1}n^{2}2^{n}=1^{2}\times 2^{1}+2^{2}\times 2^{2}+3^{2}\times 2^{3}+\ldots +10^{2}\times 2^{10}$
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