Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 32

Answer

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An arithmetic sequence is a sequence whose terms are obtained by adding the same fixed constant $d$ to each term to get the next term. Thus an arithmetic sequence has the form $a, a+d, a+2d, a+3d, \ldots$ $a_{n}=a+(n-1)d$ ------------ Let $d_{1}$ be the common difference in the arithmetic sequence $a_{1},\ a_{2},\ a_{3},\ \ldots$, $a_{n}=a_{1}+(n-1)d_{1}$, Let $d_{2}$ be the common difference for $b_{1},\ b_{2},\ b_{3},\ \ldots$, $b_{n}=b_{1}+(n-1)d_{2}$. Now, observe the sequence $a_{1}+b_{1},\ a_{2}+b_{2},\ \ldots$, where $a_{n}+b_{n}=[a_{1}+(n-1)d_{1}]+[b_{1}+(n-1)d_{2}]$ $a_{n}+b_{n}=(a_{1}+b_{1})+(n-1)(d_{1}+d_{2})$, So, $a_{1}+b_{1},\ a_{2}+b_{2},\ \ldots$ is an arithmetic sequence with first term $a_{1}+b_{1}$ and common difference $d_{1}+d_{2}$.
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