Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 46

Answer

$\sum ^{100}_{k=1}k^{2}$

Work Step by Step

$1^{2}+2^{2}+3^{2}+\ldots +100^{2}=\sum ^{100}_{k=1}k^{2}$
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