Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 13

Answer

(a) $a_1=\frac{3}{4}$ $a_2=\frac{9}{8}$ $a_3=\frac{27}{16}$ $a_4=\frac{81}{32}$ $a_5=\frac{243}{64}$ (b) See the graph. (c) $S_5=\frac{633}{64}$ (d) It is a geometric sequence. Common ratio: $r=\frac{3}{2}$

Work Step by Step

$a_n=\frac{3^n}{2^{n+1}}$ (a) $a_1=\frac{3^1}{2^{1+1}}=\frac{3}{4}$ $a_2=\frac{3^2}{2^{1+2}}=\frac{9}{8}$ $a_3=\frac{3^3}{2^{1+3}}=\frac{27}{16}$ $a_4=\frac{3^4}{2^{1+4}}=\frac{81}{32}$ $a_5=\frac{3^5}{2^{1+5}}=\frac{243}{64}$ (c) $S_5=a_1+a_2+a_3+a_4+a_5=\frac{3}{4}+\frac{9}{8}+\frac{27}{16}+\frac{81}{32}+\frac{243}{64}=\frac{633}{64}$ (d) $\frac{a_2}{a_1}=\frac{3}{2}$ $\frac{a_3}{a_2}=\frac{3}{2}$ $\frac{a_4}{a_3}=\frac{3}{2}$ $\frac{a_5}{a_4}=\frac{3}{2}$ It is a geometric sequence. Common ratio: $r=\frac{3}{2}$
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