Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 22

Answer

$1/a^3$ and Geometric

Work Step by Step

When we subtract successive terms we see there is no common difference. Then we must check for a common ratio. When we divide successive terms we get 1/a for all divisions. Thus the sequence is geometric and the fifth term is the last term times 1/a which is $1/a^3$
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