Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 890: 34

Answer

a) yes it will be arithmetic sequence too b) yes it will be geometric sequence too

Work Step by Step

If $a_{1},a_{2},a_{3}\ldots $ an arithmetic sequence then $a_{3}-a_{2}=a_{2}-a_{1}$ In order $a_{1}+2,a_{2}+2,a_{3}+2\dots $ be an arithmetic sequence $\left( a_{3}+2\right) -\left( a_{2}+2\right) =\left( a_{2}+2\right) -\left( a_{1}+2\right) $ $\left( a_{3}+2\right) -\left( a_{2}+2\right) =\left( a_{2}+2\right) -\left( a_{1}+2\right) \Rightarrow a_{3}-a_{2}=a_{2}-a_{1}$ so this is arithmetic sequence too If $5a_{1},5a_{2},5a_{3}\ldots $ is a geometric sequence then $\left( 5a_{3}\right) \times \left( 5a_{1}\right) =\left( 5a_{2}\right) ^{2}\Rightarrow a_{3}\times a_{1}=a^{2}_{2}$ and we already know this is true becouse $a_{1},a_{2},a_{3}\dots $ is a geometric sequence
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