Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 52

Answer

$\approx 4.9986$

Work Step by Step

We have to compute the sum of the geometric sequence: $2+\dfrac{6}{5}+\dfrac{18}{25}+...+2\left(\dfrac{3}{5}\right)^{15}$ The sum can be written as: $\sum_{n=1}^{16} 2\left(\dfrac{3}{5}\right)^{n-1}$ The elements of the geometric sequence are: $a_1=2$ $r=\dfrac{3}{5}$ $n=16$ Use a graphing utility to find the sum of the geometric sequence: $sum\left(seq\left(2\left(\dfrac{3}{5}\right)^{n-1},n,1,16\right)\right)\approx 4.99858944505\approx 4.9986$
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